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0.04x^2-169=0
a = 0.04; b = 0; c = -169;
Δ = b2-4ac
Δ = 02-4·0.04·(-169)
Δ = 27.04
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{27.04}}{2*0.04}=\frac{0-\sqrt{27.04}}{0.08} =-\frac{\sqrt{}}{0.08} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{27.04}}{2*0.04}=\frac{0+\sqrt{27.04}}{0.08} =\frac{\sqrt{}}{0.08} $
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